x2−95x+300=x11\sqrt{x^2 - 95x + 300} = x \sqrt{11}x2−95x+300=x11What are all possible solutions to the given equation?A52\dfrac{5}{2}25B−52-\dfrac{5}{2}−25 and 121212C121212D52\dfrac{5}{2}25 and −12-12−12Check answerShow answerExplanationSquare both sides: x2−95x+300=11x2x^2 - 95x + 300 = 11x^2x2−95x+300=11x2, 10x2+95x−300=010x^2 + 95x - 300 = 010x2+95x−300=0, 2x2+19x−60=02x^2 + 19x - 60 = 02x2+19x−60=0. Solutions x=52x = \dfrac{5}{2}x=25, x=−12x = -12x=−12. Check: Only x=52x = \dfrac{5}{2}x=25 works (right side ≥0\geq 0≥0, domain).
