In the equation x2+(k−3)x+36=0x^2 + (\sqrt{k} - 3)x + 36 = 0x2+(k−3)x+36=0, kkk is a constant. The equation has exactly one real solution. What is the value of kkk?A225B168C165D15Check answerShow answerExplanationDiscriminant = 0: (k−3)2−144=0(\sqrt{k} - 3)^2 - 144 = 0(k−3)2−144=0, so k=3+12\sqrt{k} = 3 + 12k=3+12, thus k=225k = 225k=225
