In the given equation x2+(k−3)x+42=0x^2 + (\sqrt{k-3})x + 42 = 0x2+(k−3)x+42=0, kkk is a constant. The equation has exactly one real solution. What is the value of kkk?A171B168C165D45Check answerShow answerExplanationFor one real solution, discriminant = 0: (k−3)2−4(42)=0(\sqrt{k} - 3)^2 - 4(42) = 0(k−3)2−4(42)=0, solving gives k=171k = 171k=171
