Answer: B) $22\sqrt{3}$

Context: Right triangle with base $= 66$, angle $30°$ at bottom-right, and vertical side $x$ opposite the $30°$ angle.

Answer: $\tan 30° = \dfrac{x}{66}$, so $x = 66 \tan 30° = 66 \cdot \dfrac{\sqrt{3}}{3} = 22\sqrt{3}$.

Why: This is a 30-60-90 triangle. The side opposite $30°$ is the short leg, found via $\tan 30° = \dfrac{1}{\sqrt{3}}$.

Traps: A) $22$ — drops $\sqrt{3}$. C) $66\sqrt{3}$ — that's the long leg (opposite $60°$). D) $132$ — that's the hypotenuse ($2 \times 66$).