Context: The graph shows a system of two equations: a horizontal line at $y = 2$ and a narrow downward-opening parabola whose vertex sits at $(-3, 2)$. The task is to give the solution $(x, y)$ of the system.

Answer: C) $(-3, 2)$

Why? A solution must lie on both graphs at once. The vertex is the parabola's highest point and it rests exactly on the line $y = 2$, with both branches falling below the line everywhere else, so the graphs touch at $(-3, 2)$ and nowhere else.

Traps:

• A) $(0, 2)$ sits on the line $y = 2$, but by $x = 0$ the parabola has dropped far below the grid, so the point is not on the curve.
• B) $(0, 3)$ lies on neither graph; the horizontal line is at $y = 2$, not $y = 3$.
• D) $(3, -2)$ reverses the signs of the vertex coordinates, giving a point that is off the line, since $y \ne 2$, and nowhere near either branch of the parabola.