Context: Graph of momentum $y$ (newton-seconds) vs time $x$ (seconds) for $0 \le x \le 8$. Marked points on the curve include $(2, 2)$ and $(6, 8)$. Find the average rate of change from $x = 2$ to $x = 6$.

Answer: 1.5

Why: Average rate of change $= \dfrac{y(6) - y(2)}{6 - 2} = \dfrac{8 - 2}{4} = \dfrac{6}{4} = 1.5$ newton-seconds per second.

Verification: The marked dots clearly sit at $(2, 2)$ and $(6, 8)$, confirming both readings. $\dfrac{6}{4} = 1.5$ exactly. ✓