y < 13x + 12 For which of the following tables are all the values of x and their corresponding values of y solutions to the given inequality?

y < 13x + 12 For which of the following tables are all the values of x and their... | SAT Linear inequalities in one or two variables Practice

$x$	$y$
2	21
4	81
6	73

$x$	$y$
2	21
4	47
6	73

$x$	$y$
2	38
4	64
6	90

$x$	$y$
2	38
4	65
6	91

Context: We need the table in which every $(x, y)$ pair satisfies $y < 13x + 12$ . At $x = 2$ , $4$ , and $6$ , the boundary values $13x + 12$ are 38, 64, and 90, so each $y$ must be strictly less than those.

Answer: B) the table with $y$ -values 21, 47, and 73 for $x = 2, 4, 6$

Why: Checking every row of that table: $21 < 38$ , $47 < 64$ , and $73 < 90$ are all true, so all three pairs are solutions to the inequality.

Traps:

A) fails in its middle row: at $x = 4$ , the pair $(4, 81)$ gives $81 < 64$ , which is false.
C) every $y$ equals $13x + 12$ exactly ( $38$ , $64$ , $90$ ); the inequality is strict, so points on the boundary line are not solutions.
D) every row fails: $38 < 38$ , $65 < 64$ , and $91 < 90$ are all false.

Question Bank

Question Bank

SAT Linear inequalities in one or two variables practice question

Explanation