Answer: B. $10(x^2+13)$

Explanation:1. **Understand the problem:** We need to find an expression that is equivalent to $10x^2+130$ by factoring out a common term if possible.

2. **Look for a common factor in the terms $10x^2$ and $130$:** The coefficients are $10$ and $130$. The greatest common divisor (GCD) of $10$ and $130$ is $10$, because $130 = 10 \times 13$.

3. **Factor out the common factor:** Factor $10$ out from both terms: $10x^2+130 = 10 \cdot x^2 + 10 \cdot 13$ Using the distributive property in reverse ($ab+ac = a(b+c)$): $= 10(x^2+13)$

4. **Compare with the given options:** The factored expression $10(x^2+13)$ matches option B.

Let's check the other options by expanding them: [A] $10(13x^2) = 130x^2 \neq 10x^2+130$ [C] $130(10x^2) = 1300x^2 \neq 10x^2+130$ [D] $130(10x^2+1) = 1300x^2+130 \neq 10x^2+130$

5. **Conclusion:** The expression equivalent to $10x^2+130$ is $10(x^2+13)$.